Welcome to the Daily Maths Challenge
Answers for yesterday’s Challenge (1.4.20)
New Maths Challenge
I will post everyone’s answers along with the correct answers in tomorrow’s Daily Maths Challenge.
Good luck!
Answers for yesterday’s Challenge (1.4.20)
I will post everyone’s answers along with the correct answers in tomorrow’s Daily Maths Challenge.
Good luck!
1.7
2.3
3.4
4.6
The first pile has 7 coins.
The second pile has 3 coins.
The third pile has 4 coins.
The last pile has 6 coins.
1st pile= 7
2nd pile= 3
3rd pile= 4
4th pile= 6
Answer:
———-
7346
First pile 7
Second pile 3
Third pile 4
Fourth pile 6
Great work so far!
That was really hard! It took us ages to work it out. My brother and I did it together because it was the challenge for both of us.
pile 1 had 7 coins
pile 2 had 3 coins
pile 3 had 4 coins and
pile 4 had 6 coins
1.7
2.3
3.4
4.5
a + b + c + d = 20
(b+4) + (b) + (b+1) + (2b) = 20
5b + 5 = 20
5b = 20 – 5
b = 15/5
b = 3
a = 7
b = 3
c = 4
d = 6
The first pile :7 coins
The second pile :3 coins
The third pile:4 coins
The fourth pile:6 coins
1=7
2=3
3=4
4=6
The first pile 7
The second pile 3
The third pile 4
The fourth pile 6
1st pile : 7 coins
2nd pile : 3 coins
3rd pile : 4 coins
4th pile : 6 coins
first pile has 7 coins
second pile has 3 coins
third pile has 4 coins
fourth pile has 6 coins
The first pile had 7 coins, the 2nd one had 3 coins, the 3rd one had 4 coins and the last one had 6 coins.
First pile=7
Second pile=3
Third pile=4
Forth pile=6
Total 20
The first pile had seven coins
The second pile had three coins
The third pile had 4 coins
The fourth pile had six coins
Hi everybody,
I just worked out the answer. The first pile has one,the second pile has three, the third pile has four the fifth pile has six.
The first stack had 7 coins.
The second one has 3.
The fourth and third stack had 4 and 6.
How did you solve your answers?
The answer is:
The first pile is 7
The second pile is 3
The third pile is 4
The fourth pile is 6
Another solution to yesterday’s task is: 6,3,5,1,4,2
My mum taught me this method:
If second pile is X, then first pile is 4+X
Third pile is X+1 and fourth pile is 2X
Then we add them all together:
(4+X) + X + (X+1)+ 2X=20
Then we group all numbers and X
4 + X +X + X + 1 + 2X=20
5X + 5= 20
5X=20-5=15
X=3
So the second pile has 3 coins
The first pile has (4+3)=7 coins
Third pile has (1+3)=4 coins and fourth pile has (2×3)=6 coins
The first pile has 7 coins
The second pile has 3 coins
The third pile has 4 coins
The fourth pile has 6 coins
1st pile
20÷2=10
10+1=11
11-4=7
2nd pile
7-4=3
3rd pile
3+1=4
4th pile
3×2=6
It was very tricky but then I got there.
1st pile20 divided by 2=10+1=11-1=7
Second pile7-4=3
3rd pile 3+1=4
4th pile 3×2=6
First pile =7
Second pile = 3
third pile = 4
fourth pile=6
7+3+4+6= 20
Great Maths work, you can check if your answers are correct in Fridays Maths challenge!