Welcome to the Daily Maths Challenge

Answers for yesterdays Challenge (25.3.20)

New Daily Challenge:

Top Tips:
1. Read the question carefully
2. Work out your method to solve the problem
3. Solve it
4. Check it
5. Write your answer on the blog

Your answers will be published on the blog at the end of the day and the answers will be given in tomorrow’s Maths challenge.

Good luck!

20 comments on “Daily Maths Challenge: 26.3.20

  1. Q1:
    1 tripod and 10 bipods/7 tripods and 1 bipod.

  2. Graceanne says:

    3+3+3+2+3+2+3+2+2=23
    4 bipods
    5tripods

  3. 4 bipods =8 legs
    5 tripods=15 legs
    15+8=23

    Or
    3 tripods= 9 legs
    7 bipods= 14 legs
    9+14=23

  4. 7 Bipods = 14 legs
    3 Tribods = 9

    4 Bipods = 8 legs
    5 Tripod = 15 legs

  5. Miss Jones says:

    Great responses so far Class 3!
    If you haven’t had a go yet, why not give it a try?! ?

  6. There are 8 tripods
    1 bipods

  7. 7×3=21
    1×2=2
    21+2=23
    So we have 7 tripods and 1 bipod

    1×3=3
    10×2=20
    20+3=23
    So we have 10 bipods an 1 tripod

  8. Hi everyone
    The answer is 4 tripods and 5 bipods to make 23 you can also make 23 using 7 bipods and 3 tripods.??????????☺️??????????

  9. I found two solutions and there are only 2 solutions because to get an odd number in total, you need an odd number of Tripods greater than 2.
    4 Bipods and 5 Tripods
    7 Bipods and 3 Tripods

  10. I worked it out by doing
    3+2=5
    23÷5=4.3
    3×5=15
    2×4=8
    15+8=23
    Answer: 5 tripods 4 bipods

    or you can work it out like this
    I used 3 because the tripod have 3 legs
    3×3=9
    23-9=14
    14÷2=7 bipods
    9+14=23
    Answer: 3 tripods and 7 bipods

  11. there are 4 tripods =12

    there are 3 bipods=6

  12. 10 Bipods + 1 Tripod = 23 legs
    7 Tripods + 1 Bipod = 23 legs

  13. There are 3 tripods and 7 bipods

  14. 7 tripods
    3 legs x 7 tripods=21
    We added one bipod to get 23 legs

    2 legs x 10 bipeds=20
    We added one tripod to get 23 legs

  15. 1 tripod =3 legs
    1 bipod=2 legs
    Altogether 23

    1. T.- 3×3=9
    B.- 2×7=14
    9+14=23

    2. B.- 2×4=8
    T.- 3×5=15
    8+15=23

  16. There are two possibilities:
    1) 3 Tripods and 7 Bipods
    3×3=9 legs
    7×2=14 legs
    9+14=23 legs
    2) 5 Tripods and 4 Bipods
    5×3=15 legs
    4×2=8 legs
    15+8=23 legs

  17. Miss Jones says:

    Well done Class 3 for posting all of your answers today. If you haven’t answered yet, there’s still some time! I will reveal the answers in tomorrow’s Maths challenge post.

  18. 1 tripod has 3 legs
    1 bipod has 2 legs
    ?
    5 tripods x 3 legs= 15 legs
    4 bipods x 2 legs = 8 legs
    15+ 8 = 23 legs
    ?
    3 tripods x 3 legs= 9 legs
    7 bipods x 2 legs = 14 legs
    14 + 9= 23 legs

  19. Answer 1. 3 tripods 7 bipods.
    Answer 2. 4 bipods 5 tripods.

  20. 1. 7 Tripods&1Bipod
    2. 5Tripods&4Bipods

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