Hello Year 5.
Can you solve this maths problem?
We will reveal the answers tomorrow morning. Please explain your working out/reasoning!
Good luck.
We look forward to reading your responses,
Mrs Avdiu & Ms Robertson
Hello Year 5.
Can you solve this maths problem?
We will reveal the answers tomorrow morning. Please explain your working out/reasoning!
Good luck.
We look forward to reading your responses,
Mrs Avdiu & Ms Robertson
Good Morning Mrs Avdiu! I was working on this maths problem in my maths learning session and I think that the answer might be three. I think it’s three because when I did four divided by fifteen I got three remainder three and it says in the question that he then could pay any sum of money without opening any of the bags. I think that any sum could be the remainder three since it would not go into all the bags evenly. ( Also, my film still hasn’t been put on so could you please upload it? Thank you! )
Thanks Elsa. I wonder if anyone agrees or has a different way or working it out? Elsa, I have uploaded three of the films but Vimeo has a weekly limit which we have exceeded for the week. Therefore I will upload the rest of the films once it allows me to. They are very big files! Thanks for your patience.
I agree with Elsa I also got three remainder three when I was working it out. I worked it out by trying my three times tables on the four bags. I got twelve so then I tried my four times tables and I got sixteen what was over fifteen, so I knew it was remainder three as on the three times tables I got twelve which is remainder three. I think the answer is three remainder three.
If you put 1p in one bag, 2p in one bag, 4p in one bag and 8p in one bag, that all adds up to 15p and you can make any number from 1p-15p without taking the money out of any bag.
Hi Gabriella
Your answer sounds logical…. we’ll find out tomorrow if you’re right.
Good afternoon Mrs Avdiu ,
I did the working out and I got 3 and 3 remainder . I divided 4 and 15 and the number the closest to 15 in the table of 4 is 12 ,so the answer is 3p in each bag and 3 left over .
Hi! I think I agree with Gabi.
1p in 1 bag
2p in 1 bag
4p in 1 bag
8p in 1 bag
total p=15
All of these sums can be added up to totals between 1-15.
If Ram puts 1p in one bag , 2p in another , 4p in the third bag and then 8p in the last bag he can add the bags together to make any amount between 1p and 15p .
Ram put 1 penny in the first bag 2 pennies in the second ,4 pennies in the third and 8 pennies in the fourth. 1+2+4+8 = 15 and with 1,2,4 and 8 , you can make any number between 1 and 15
I also agree with Gabi, Ayako and Lavinia. I think that he should put 1p in one, 2p in another, 4p in another and 8p in the last bag as he can always make the bags add up to a total from 1-15p.
If Ram puts 1p in 1 bag,2p in 1 bag,4p In 1 bag and 8p in 1 bag the total will be 15p.All of these bags can be added up to totals between 1-15.
Good Afternoon Mrs Avdiu and Ms Robertson,
I agree with most of the following answers above. If Ram puts 1p, 2p, 4p and 8p in the four bags the total would be 15. Any sum from 1p to 15p can be made with these amounts.
Hello everyone! What about this:
3p in one bag
4p in each of the remaining bags
4p x 3bags = 12p
3p + 12p = 15p
Good morning Mrs Avdiu and Ms Robertson. I also agree with everyone who said that Ram puts 1p, 2p, 4p and 8p in the bags as all these bags add up to make a total from 1-15p.